# Can u solve this??

Geometry Level pending

Let $$ABC$$ be a triangle with $$AB = AC$$. If $$D$$ is the mid point of $$BC$$, $$E$$ the foot of perpendicular drawn from $$D$$ to $$AC$$ and $$F$$ the mid point of $$DE$$, $$AF$$ and $$BE$$ are joined and meet at $$M$$.

What is the measure of the angle $$AMB$$?

P.S. please post a pure geometrical proof of this (without use of coordinate geometry)

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