# New Year Puzzle

Number Theory Level pending

A four-digit number, $$\overline{abcd}$$ (in base 10) can be expressed as $$\overline{abcd}=1000a+100b+10c+d$$. If we change this formula to $$998a+102b+98c+a+1$$, for $$1000<\overline{abcd}<9999$$, how many times does $$\overline{abcd}=998a+102b+98c+d+1$$?

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