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limn→∞1n∑r=12nrn2+r2=a−1, a= ?\large \lim_{n\rightarrow \infty} \dfrac{1}{n} \displaystyle\sum_{r=1}^{2n} \dfrac{r}{\sqrt{n^2+r^2}} = \sqrt{a} - 1, \ \ \ \ \ \ \ a = \ ? n→∞limn1r=1∑2nn2+r2r=a−1, a= ?
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