# NMTC 2014(Junior level)

Geometry Level 3

In the given figure, $$PQ=42\text{ cm}$$. $$QR$$ is the tangent to the semicircle at $$Q$$. If the difference of the areas of region $$A$$ and $$B$$ is $$357\text{ cm}^2$$, then the base $$QR$$ of the right triangle $$PQR$$ is (in cm)(Take $$\pi=\frac{22}{7}$$)

Note: This problem has appeared in nmtc 2014 junior level.

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