NMTC 2014(Junior level)

Geometry Level 3

In the given figure, \(PQ=42\text{ cm}\). \(QR\) is the tangent to the semicircle at \(Q\). If the difference of the areas of region \(A\) and \(B\) is \(357\text{ cm}^2\), then the base \(QR\) of the right triangle \(PQR\) is (in cm)(Take \(\pi=\frac{22}{7}\))

Note: This problem has appeared in nmtc 2014 junior level.

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