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{abc=2a2b3c4=5a−1b7c−2=9\large \begin {cases} abc = 2 \\ a^{2}b^{3}c^{4} = 5 \\ a^{-1}b^{7}c^{-2} = 9 \end {cases} ⎩⎪⎪⎨⎪⎪⎧abc=2a2b3c4=5a−1b7c−2=9
If a,b,a, b,a,b, and ccc are real numbers, determine (a+b+c) (a + b + c) (a+b+c), to two decimal places.
Hint: Can you find a clever way of representing this as a linear system?
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