Not hard to imagine

Geometry Level 5

$$ABCD$$ is a square with area $$k$$. $$E$$ is a point on $$\overline{BC}$$ such that $$\overline{BE}:\overline{EC}=2:3$$ and $$F$$ a point on $$\overline{AD}$$ such that $$\overline{DF}:\overline{FA}=5:7$$. If G is the intersection point between $$\overline{AE}$$ and $$\overline{BF}$$. The area of triangle $$AGB$$ can be written as $$\frac{a}{b}k$$. Find $$a+b$$

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