Not hard to imagine

Geometry Level 5

\(ABCD\) is a square with area \(k\). \(E\) is a point on \(\overline{BC}\) such that \(\overline{BE}:\overline{EC}=2:3\) and \(F\) a point on \(\overline{AD}\) such that \(\overline{DF}:\overline{FA}=5:7\). If G is the intersection point between \(\overline{AE}\) and \(\overline{BF}\). The area of triangle \(AGB\) can be written as \(\frac{a}{b}k\). Find \(a+b\)

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