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If
∫01(−3)xdx=−a+ib\large{\displaystyle{\int _{ 0 }^{ 1 }{ { (-3) }^{ x } } dx=-a+ib}}∫01(−3)xdx=−a+ib
where ii i is imaginary unit. Find ⌊100ab⌋\left\lfloor 100ab \right\rfloor ⌊100ab⌋.
Note: That the principal value of the complex exponentiation.
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