Mayank and Akul have been busy with their JEE preparation so Mayank thought of adding a small question without much story line

Solve

\[ \frac { dy }{ dx } =\frac { 3xy^{ 4 }+2y }{ x-2x^{ 2 }y^{ 3 } }\]

where \(x\ne 0 \), you're given that \(y = 1 \) when \(x=-1\). Find the value of \(x\) when \(y = -0.5\).

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