# Now solve it

Calculus Level 5

Mayank and Akul have been busy with their JEE preparation so Mayank thought of adding a small question without much story line

Solve

$\frac { dy }{ dx } =\frac { 3xy^{ 4 }+2y }{ x-2x^{ 2 }y^{ 3 } }$

where $$x\ne 0$$, you're given that $$y = 1$$ when $$x=-1$$. Find the value of $$x$$ when $$y = -0.5$$.

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