$n^\text{th}$ derivative?

Calculus Level 3

If $n$ is a non-negative integer, find the $n^\text{th}$ derivative of $\dfrac{\ln x}x$ .

\frac{ {(-1 }^{n}n!}{ {x}^{ n+1}} \left(\ln(x)-\sum _{ k=1 }^{ n }{ \frac { 1 }{ k } } \right)

x(\ln(x)-x)

\frac{{(-1)}^{n-1}n! }{{x}^{n}}\left (\ln(x-n)-\sum _{ k=1 }^{ n }{ \frac { 1 }{ k } } \right)

Cannot be determined

\ln(x)-x

nth n^\text{th} nth derivative?