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\( n^{th} \) root limit!

Calculus Level 1

For a constant \(k\),

\[ \lim_{ n \to \infty } n^{n^{-1} } = e^k .\]

Find the value of \( \log_{e} ( k^2 +1 ). \)

\[ \dfrac { \pi}{\pi - 1} \] 0.512 0 1

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by Kunal Joshi

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