Starting at "Start" with a value \( x \) at 0, and then travelling among the maze adding and subtracting to \( x \) as specified, is it possible to leave the maze with \( x \) at 1?

It is possible to cycle back and forth between two rooms, but the value of 1 must be had at the exit, not just midway through the path.

For example, one possible path from Start (which doesn't succeed) would be to +2 \( (x = 2), \) -3 \( (x = -1), \) +2 \( (x = 1), \) + 6 \( (x = 7), \) -1 \( (x = 6). \)

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