The functions \(\text{f}\) and \(\text{g}\) are defined for all real values of \(x\) by \[\text{f}(x) = x^2+4ax+a^2 \quad \text{and} \quad \text{g}(x)=4x-2a\] where \(a\) is a positive constant.

\((\text{i})\) Find the range of \(\text{f}\) in terms of \(a\).

\((\text{ii})\) Given that \(\text{fg}(3)=69\), find the value of \(a\) and hence find the value of \(x\) such that \(\text{g}^{-1}(x)=x\).

**Input \(3 \times\) the value of \(x\) from part \((\text{ii})\) as your answer.**

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