# OCR A Level: Further Pure 3 - Complex Numbers [January 2010 Q7]

**Algebra**Level 4

\((\text{i})\) Solve the equation \(\cos 6 \theta = 0\), for \(0<\theta<\pi\).

\((\text{ii})\) By using de Moivre's theorem, show that \[\cos 6 \theta \equiv (2 \cos^2 \theta -1)(16 \cos^4 \theta - 16\cos^2 \theta +1).\]

\((\text{iii})\) Hence find the exact value of \[\cos \left (\dfrac{\pi}{12} \right ) \cos \left (\dfrac{5 \pi}{12} \right ) \cos \left (\dfrac{7 \pi}{12} \right ) \cos \left (\dfrac{11 \pi}{12} \right )\] justifying your answer.

**If your answer to part \((\text{iii})\) is \(\dfrac{a}{b}\) for co-prime integers \(a\) and \(b\), input \(a+b\) as your answer.**