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Suppose that
A=∑i=0∞(12i+1−12i+2). A = \sum_{i=0}^\infty \left( \frac{1}{ 2i+1} - \frac{1} { 2i + 2 } \right). A=i=0∑∞(2i+11−2i+21).
What is the value of
∑i=0∞(14i+1+14i+3−12i+2)? \sum_{i=0}^\infty \left(\frac{ 1 } { 4i+1} + \frac{1}{ 4i+3} - \frac{1}{2i+2} \right)? i=0∑∞(4i+11+4i+31−2i+21)?
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