Forgot password? New user? Sign up
Existing user? Log in
f(x)=x3−2x2+6x−1=0f(x)=x^3-2x^2+6x-1=0f(x)=x3−2x2+6x−1=0
The three roots of the above equation are α,β,γ\alpha,\beta,\gammaα,β,γ, then what is
αα2−α+1+ββ2−β+1+γγ2−γ+1=?\frac{\alpha}{\alpha^2-\alpha+1}+\frac{\beta}{\beta^2-\beta+1}+\frac{\gamma}{\gamma^2-\gamma+1}=?α2−α+1α+β2−β+1β+γ2−γ+1γ=?
Problem Loading...
Note Loading...
Set Loading...