# % of $$\ce{NaCl}$$

Chemistry Level pending

A mixture of $$\ce{CaCl_2}$$ and $$\ce{NaCl_2}$$ of mass $$4.44\text{ g}$$ is treated with $$\ce{Na_2CO_3}$$ solution to precipitate all $$\ce{Ca^{2+}}$$ ions to $$CaCO_3. CaCO_3$$ so obtained is heated strongly to get $$0.56\text{ g}$$ of $$\ce{CaO}$$. The % of $$\ce{NaCl_2}$$ in the mixture(at mass of Ca=40)

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