Oh dear 11!

Find the remainder when k=1100k(k!)\sum_{k=1}^{100} k(k!) is divided by 11.


Details:-

\bullet k!k! stands for factorial of kk, that is k!=k×(k1)×(k2)×...×2×1k!=k\times (k-1)\times (k-2) \times ... \times 2 \times 1


This is a part of the set 11≡ awesome (mod remainders)

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