Oleum!

Chemistry Level 4

0.5 grams of Oleum is diluted with \(\ce {H2O}\) . The resultant solution required 26.7 ml of 0.4 N NaOH solution for complete neutralisation. Find the percentage of free \(\ce {SO3}\) in the sample of Oleum and also find Label for oleum

Enter your answer as sum of the values (up to 2 decimal places).

Note: Label is actually the final weight of \(\ce {H2SO4}\) after complete conversion of 100gm oleum mixture(\(\ce {SO3}\) & \(\ce {H2SO4}\)) to sulfuric acid after addition of water.


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This is a part of my set: Aniket's Chemistry Challenges. (BEST OF JEE - ADVANCED)
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