OMG! Steam+Ice+Water

An Insulated Vessel Contains 0.4 kg of water at 273 K . A Piece Of 0.1 kg Ice At 258 K Is Put Into It And Steam At

373 K Is Bubbled Into It Untill All Ice Melts And Finally The Vessel Contains Only Liquid Water At 313 K .

Assume That Vessel Does Not Give Or Take Any Heat And There Is No Loss Of Matter And Heat To


Calculate The Amount Of Steam That Was Bubbled Into Water Initially.

Details And Assumptions

Specific Heat Of Ice = 2200 J/kg K

Heat Of Fusion Of Water = 333000/kg

Heat Of Vapourization Of Water = 2260000 J/kg

Give Your Answer In Grams

Round Of The Answer To The Nearest Integer


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