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S=∑n=1∞σ2(n)n6S=\sum_{n=1}^{\infty}\frac{\sigma_2(n)}{n^6}S=n=1∑∞n6σ2(n)
Let σ2(n)\sigma_2(n)σ2(n) denote the sum of the squares of all the positive integer divisors of nnn. For example, σ2(6)=12+22+32+62=50\sigma_2(6)=1^2+2^2+3^2+6^2=50σ2(6)=12+22+32+62=50.
Enter π10S\frac{\pi^{10}}{S}Sπ10 as your answer.
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