Just Divide and Conquer.

Calculus Level 5

 limnk=1nλk4+2k3+k2+k+13n5+n2+n+5k=13\large\ \lim _{ n\rightarrow \infty }{ \sum _{ k=1 }^{ n }{ \frac { \lambda { k }^{ 4 } + 2{ k }^{ 3 } + { k }^{ 2 } + k + 1 }{ { 3n }^{ 5 } + { n }^{ 2 } + n + 5k } } } = \frac { 1 }{ 3 }

Find λ\lambda if the equation above holds true.

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