The period of Earth's orbit around the sun is 365 days. Given that the mass of the sun is about \(2 \times 10^{30} \text{ kg}\), compute the velocity to the nearest 1000 meters per second of the Earth as it orbits the sun. Approximate the orbit of the Earth around the sun as circular.

**Useful constant**: Newton's gravitational constant is \(6.67\times 10^{-11} \text{ N} \cdot \text{m}^2 / \text{kg}^2\).

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