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Solve the following differential equation:(x2−4x+4)y′′+(4x−8)y′+2y=0({x}^{2}-4x+4)y''+(4x-8)y'+2y=0(x2−4x+4)y′′+(4x−8)y′+2y=0 where y(0)=1/2y(0)=1/2y(0)=1/2 y′(0)=1/4.y'(0)=1/4.y′(0)=1/4.
Ifthe sum of the first 10 terms of the power series expansion for y(x)y(x)y(x) is ab\frac{a}{b}ba calculate a+ba+ba+b.
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