Over n out!!
A battery of \(10V\) and neglegible internal resistance is connected across the diagonally opposite corners of a cubical network consisting of \(12\) resistors each of \(1 \Omega\). The current \(I\) flows through the circuit.
\(\rightarrow I\) should be in \(ampere\).
\(\rightarrow\)All resistances in the image above are of \(1 \Omega\) and battery is of \(10V\).
\(\rightarrow\)It's a question from \(KVPY\).
Image credit: \(Akshat\) \(Sharda\) \(\ddot \smile\)