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$\dfrac{1}{ax^2 + bx + c } = \dfrac{A}{x - \dfrac{-b + \sqrt{b^2 - 4ac}}{2a}} + \dfrac{B}{x - \dfrac{-b - \sqrt{b^2 - 4ac}}{2a}}$

Assume that $ax^2 + bx + c \neq 0$. Find $A+B$.

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