Particle in a time varying curve

A particle moves along the curve such that its position vector is given as a function of time as R=(t34t)i^+(t2+4t)j^+(8t23t3)k^\vec{R}=(t^3-4t) \hat { i } +(t^2+4t) \hat { j }+(8t^2-3t^3) \hat { k } where tt denotes time. The magnitude of acceleration along the normal at time t=2t=2 can be represented as PQP\sqrt{Q}

where P,QP,Q are integers and QQ square free.

Find P+QP+Q

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