# Particles in triangular motion

Classical Mechanics Level pending

Any three particles $$A$$, $$B$$ and $$C$$ are situated at the vertices of a triangular shaped wooden board $$ABC$$ of identical side length $$l$$ at time $$t = 0$$ (in seconds).

If each of the particles moves with constant speed $$v$$ (in $$\text{ m/s}$$) and the velocity of particle $$A$$,$$B$$ and $$C$$ is always along $$AB$$, $$BC$$ and $$CA$$ respectively.

Then at what time(in seconds) will these particles meet each other ?

Detail and Assumptions:

• $$v = 2\text{ m/s}$$.

• $$l = 6\text{ m}$$.

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