An AC power supply with a voltage (\(V_s\)) of \(30V\) and a frequency (\(f\)) of \(25Hz\) was connected to a circuit of five inductors: \(L_1=\frac{17}{\pi}H\), \(L_2=\frac{13}{\pi}H\), \(L_3=\frac{7}{\pi}H\), \(L_4=\frac{19}{\pi}H\), and \(L_5=\frac{4}{\pi}H\).

Determine the current (\(I\)) of this circuit in \(mA\).

\(Note:\) \[X_L = 2 \pi f L_{circuit} \\ I = \frac{V_s}{X_L} \]

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