Photo-electric emission!

Photons of energy \(5eV\) fall on the surface of a metal \(X\) resulting in the emission of photo-electrons having maximum kinetic energy \(E(eV)\) and de-Broglie wavelength \(\lambda\). \(Y\) is another metal on the surface of which photons of energy \(6eV\) are incident and results in emission of photo-electrons of maximum kinetic energy \((E-2)eV\) and de-Broglie wavelength \(\sqrt3 \lambda\). Work functions of metals \(X\) & \(Y\) are in the ratio of?

Image Credit: Wikimedia Pieter Kuiper.
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