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18π(sin−1(35)+sin−1(1213)+sin−1(6365))= ? \large \frac1{8\pi} \left( \sin^{-1} \left(\frac35\right) + \sin^{-1} \left(\frac{12}{13}\right) + \sin^{-1} \left(\frac{63}{65} \right) \right) = \ ? 8π1(sin−1(53)+sin−1(1312)+sin−1(6563))= ?
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