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Evaluate: ∫−∞∞eaxex+1 dx\displaystyle \int_{-\infty}^{\infty} \frac{e^{ax}}{e^x + 1} \,dx∫−∞∞ex+1eaxdx when a=12a = \frac{1}{2}a=21
Bonus.- Find a beautiful closed form for the above integral being 0<a<10 < a < 10<a<1
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