\(\pi\) madness 1

In the first \(1,000,000\) digits of \(\pi\), there are \(2\) digits that occur the same number of times. Let the number of times it occurs be \(A\), and the digits be \(B\) and \(C\). Find \[A\times B\times C\]

Feel free to search for any derivations of \(\pi\)

\(\textbf{Details and Assumptions}\)

\(\bullet\) The first \(1,000,000\) digits of \(\pi\) includes the \(3\) in \(3.1415...\), so if the number is \(3.1415\) there are \(5\) digits in that number.

\(\bullet\) Supposing the \(2\) digits that occur the same number of times is \(1\) and \(2\) and the number of times it occurs is \(100\) times, the answer would be \[1\times 2\times 100=\boxed{200}\]

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