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1+14+19+116+…=π261+19+125+149+…= ?\begin{aligned}\large 1+\frac{1}{4}+\frac{1}{9}+\frac{1}{16}+\ldots &=& \large \frac{π^2}{6} \\ \large 1+\frac{1}{9}+\frac{1}{25}+\frac{1}{49}+\ldots &=& \large \ ? \end{aligned} 1+41+91+161+…1+91+251+491+…==6π2 ?
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