# Placing letters was never a big deal

$\begin{array} {} \text{Row 1:} & \Huge \Box \Box \Box \Box \\ \text{Row 2:} & \Huge \Box \Box \\ \text{Row 3:} & \Huge \Box \Box \end{array}$

Let $$K$$ be the number of different ways the letters of the word "JUMPED" can be placed in the boxes shown above so that no row is empty.

Find the value of $$\dfrac{K}{260}$$.

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