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If f(x+y+1)=(f(x)+f(y))2f(x+y+1) = \left(\sqrt{f(x)} + \sqrt{f(y)}\right)^2f(x+y+1)=(f(x)+f(y))2 and f(0)=1f(0) =1 f(0)=1, find the sum of digits of f(2014)f(2014)f(2014).
Also try Play with functions 4
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