This is a problem that I designed two years ago while I was playing with a set square.

Well, as shown below, there are two right-angled triangles ABE and ADC that share the point A where is located the right angle.Knowing that \(\overline{AB}\)=*36* \(\overline{AD}\)=*28*
Find the area of the triangle *EFC*

*Round your answer to 3 decimal places*

*Clarification:*
\(\overline{EB}\) meet \(\overline{CD}\) at F

A,E and C belong to the same line.

A,D and B belong to the same line.

\(\angle\)ABE=\(\angle\)AEB=\(45^{\circ}\)

\(\angle\)ADC=\(60^{\circ}\)

(The picture above is a scale drawing)

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