# Playing with graphs 3

Calculus Level pending

$y=\left \lfloor 6+x \left \lfloor \frac{1}{x}\right \rfloor \right \rfloor , \quad y^{2}-18x+18=0,\quad 6x-5y-6=0$

Find the area bounded by curves above for $$x>1$$.

Notation: $$\lfloor \cdot \rfloor$$ denotes the floor function.

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