# Point on the Bisector

Geometry Level 4

$$ABC$$ is a triangle with $$\angle BAC = 60^\circ, AB =5$$ and $$AC = 25$$. $$D$$ is a point on the internal angle bisector of $$\angle BAC$$ such that $$BD=DC$$. What is $$AD^2$$?

Details and assumptions

It is $$\color{red} {\mbox{not} }$$ stated that $$D$$ lies on $$BC$$. This assumption is not necessarily true.

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