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Let f(x)=x4+ax3+bx2+cx+df\left( x \right) ={ x }^{ 4 }+a{ x }^{ 3 }+b{ x }^{ 2 }+cx+df(x)=x4+ax3+bx2+cx+d, for that a,b,c,da,b,c,da,b,c,d are constants. If f(1)=1993,f(2)=3986,f(3)=5979f\left( 1 \right) =1993,\quad f(2)=3986,\quad f(3)=5979f(1)=1993,f(2)=3986,f(3)=5979. Calculate the value of 14[f(11)+f(−7)]\frac { 1 }{ 4 } [f(11)+f(-7)]41[f(11)+f(−7)].
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