# Posted the problem backwards

Geometry Level 3

$$\triangle ABC$$ has sides $$a, b, c$$ such that $$\frac{1}{a+c}+\frac{1}{b+c}=\frac{3}{a+b+c}$$. Find $$\angle C$$

Clarification: $$a$$ is the side opposite to vertex $$A$$ and $$b$$ is the side opposite to side vertex $$B$$ and $$c$$ is the side opposite to vertex $$C$$ as shown in the image above.

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