Let \(A\) be the set of all two-digit integers for which the product of their digits is exactly twice as much as the sum of their digits.
Let \(B\) be the set of all two-digit integers which become 75% greater when the digits are flipped.
Let \(n\) be the number of two-digit integers in the union \(A \cup B\).
Let \(x\) be the only two-digit integer that is a member of the intersection \(A \cap B\).
How much is \(n + x\)?