# Probability-5

**Discrete Mathematics**Level 4

Two person \(A\) and \(B\) throw a (fair) die ( six-faced cube with face no. \(1\) to \(6\)) alternatively, starting with \(A\). The first person to get an outcome different from the previous one by the opponent wins. The probability that \(B \) wins is \(\frac{x}{y}\). Then \(x+y\) is

Note: \(\gcd ( x,y )\) is \(1\)

For more problems try my set