Question 12

Geometry Level 4

As shown in the figure, \(\angle{BAC}=\angle{BCA}=44^\circ\)in \(\Delta{ABC}\). \(M\) is a point in \(\Delta{ABC}\) that \(\angle{MCA}=30^\circ\), \(\angle{MAC}=16^\circ\). Find \(\angle{BMC}\).

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