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3(12+42+92+162+…+20252)2+2(12+42+92+162+…+20252)+1 \begin{aligned} && 3(1^{2}+4^{2}+9^{2}+16^{2}+\ldots+2025^{2})^{2} \\&&+2(1^{2}+4^{2}+9^{2}+16^{2}+\ldots+2025^{2})+1 \end{aligned} 3(12+42+92+162+…+20252)2+2(12+42+92+162+…+20252)+1Find the remainder when the number above is divided by (42+92+162+…+20252)(4^{2}+9^{2}+16^{2}+\ldots +2025^{2})(42+92+162+…+20252).
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