\[\frac{3x+2y}{6}+\frac{x+2y}{12}+\frac{x+6y}{72}+\frac{x+18y}{432}+\ldots=6\]

\[\frac{4x+3y}{6}+\frac{8x+3y}{18}+\frac{16x+3y}{54}+\frac{32x+3y}{162}+\ldots=\frac{107}{8}\]

Find the value of \(x+y\).

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