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For all positive integers n\large nn,
13+23+33+⋯+n3=n2(n+1)24\large 1^3 + 2^3 + 3^3 + \cdots + n^3 = \frac {n^2(n + 1)^2}{4}13+23+33+⋯+n3=4n2(n+1)2
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