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In the given figure above O is the centre of the circle, BC and CD are two equal chords and ∠OBC=70∘\angle OBC = 70 ^ \circ∠OBC=70∘. You have to find sum of ∠BAC+∠BFD+∠CED\angle BAC+\angle BFD+\angle CED∠BAC+∠BFD+∠CED(in degrees).
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