# Pulchritude

**Calculus**Level pending

\[\sum_{1\leq n_1<n_2<n_3}\frac{1}{n_1^2 n_2^2 n_3^2}\] If the above expression equals \(\displaystyle \frac{\pi^r}{s}\), where \(r\) and \(s\) are positive integers, what is \(r+s\)?

Here is the summation expanded to the "first" 10 terms:

\(\frac{1}{ 1 ^2\cdot 2 ^2\cdot 3 ^2}+\frac{1}{ 1 ^2\cdot 2 ^2\cdot 4 ^2}+\frac{1}{ 1 ^2\cdot 3 ^2\cdot 4 ^2}+\frac{1}{ 2 ^2\cdot 3 ^2\cdot 4 ^2}+ \frac{1}{ 1 ^2\cdot 2 ^2\cdot 5 ^2}+\)

\(\frac{1}{ 1 ^2\cdot 3 ^2\cdot 5 ^2}+\frac{1}{ 1 ^2\cdot 4 ^2\cdot 5 ^2}+\frac{1}{ 2 ^2\cdot 3 ^2\cdot 5 ^2}+\frac{1}{ 2 ^2\cdot 4 ^2\cdot 5 ^2}+\frac{1}{ 3 ^2\cdot 4 ^2\cdot 5 ^2}+\ldots\)

The sum is taken over all **unordered** triples \(\{n_1,n_2,n_3\}\) of **distinct** positive integers.

Alternatively, this can be represented as \(\displaystyle\sum_{n_3=3}^{\infty}\sum_{n_2=2}^{n_3-1}\sum_{n_1=1}^{n_2-1}\frac{1}{n_1^2 n_2^2 n_3^2}\).