Pure binomial

Probability Level 3

j=010i=0j[(10j)×(ji)] \displaystyle \sum_{j=0}^{10} \sum_{i=0}^j \left [ \dbinom{10}{j} \times \dbinom{j}{i} \right ]

Find the last two digits of the double summation above.

×

Problem Loading...

Note Loading...

Set Loading...