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Consider the following equation (proved).
a=ba×a=b×aa2=aba2−b2=ab−b2(a+b)(a−b)=b(a−b)a+b=bb+b=b2b=b2=1a = b \\ a \times a = b \times a \\ a^{2} = ab \\ a^{2} - b^{2} = ab - b^{2} \\ (a + b)(a - b) = b(a - b) \\ a + b = b \\ b + b = b \\ 2b = b \\ 2 = 1a=ba×a=b×aa2=aba2−b2=ab−b2(a+b)(a−b)=b(a−b)a+b=bb+b=b2b=b2=1
Is the proof correct?
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